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方程4X-3Y-6Z=0 X+2Y-7Z=0 求方程(2XY+3yz-6zx)/(x^2+5y^2的值.
人气:333 ℃ 时间:2020-06-25 19:29:39
解答
4x-3y-6z=0(1)
x+2y-7z=0(2)
(1)-(2)×4
-3y-8y-6z+28z=0
11y=22z
y=2z
令z=k,则y=2k
所以x=7z-2y=7k-4k=3k
(2xy+3yz-6zx)/(x²+5y²)
=(12k²+6k²-18k²)/(9k²+20k²)
=0
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