已知二次函数y=2x2-4x-6,
(1)求证:该抛物线与x轴一定有两个交点;
(2)若该抛物线与x轴的两个交点分别为A、B,且它的顶点为P,求△ABP的面积.
人气:401 ℃ 时间:2019-12-01 13:26:05
解答
(1)△=b2-4ac=(-4)2-4×2×(-6)=64∵△>0,∴该抛物线一定与x轴有两个交点.(2)根据题意,得2x2-4x-6=0 ①解①得x1=-1,x2=3即A(-1,0),B(3,0),∴在△ABP中,AB=4,∵PC=|4...
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