已知tan a=2求sin的平方a-3sin a cos a+1的值
人气:104 ℃ 时间:2020-04-06 07:40:06
解答
tanA=sinA/cosA=2
则:sinA=2cosA
且:(cosA)^2=1/[1+(tanA)^2]=1/5
故:(sinA)^2-3sinAcosA+1
=(2cosA)^2-6(cosA)^2+1
=1-2(cosA)^2
=1-2/5
=3/5
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