x^7÷x^2×x^3-2（x^2）^3×x^2+(x^2)^6÷（-x）^4+[(x^3÷x^2÷x)^0+1]^2
=x^(7-2+3)-2x^(2×3+2)+x^(2×6-4)+(1+1)^2
=x^8-2x^8+x^8+2^2
=4