=3/x(x+2) -1/x(x-2)
=[3(x-2)-(x+2)]/x(x+2)(x-2)
=(2x-8)/(x ³-4x)不好意思，我在后面少打了个＝0，可以再答一遍吗？3/x(x+2) -1/x(x-2)=0两边乘以x(x+2)(x-2)得3(x-2)-(x+2)=02x-8=0x=4检验：x=4是方程的解