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先化简,再求值,[(a+b)^2/a]-[a-(2ab-b^2)/a],其中a=2011,b=2012
人气:282 ℃ 时间:2020-04-04 08:48:26
解答

[(a+b)²/a-[a-(2ab-b²)/a]
=(a+b)²/a-[(a²-2ab+b²)/a]
=(a²+2ab+b²)/a-(a²-2ab+b²)/a
=(4ab)/a
=4b
=4×2012
=8048
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