若m等于它的倒数
即m=1/m m²=1
m=±1
(m²+m-6)/(m-2)÷(m+3)/(m²-3m+1)
=[(m+3)(m-2)/(m-2)]*[(m²-3m+1)/(m+3)]
=m²-3m+1
=1-3m+1
=2-3m
=-1或5非常感谢您！能不能详细解一下(m²+m-6)/(m-2)÷(m+3)/(m²-3m+1)的过程(m²+m-6)/(m-2)÷(m+3)/(m²-3m+1)=[(m+3)(m-2)/(m-2)]*[(m²-3m+1)/(m+3)]=(m+3)*(m²-3m+1)/(m+3)=m²-3m+1=1-3m+1=2-3m=-1或5你看已经很详细，都是约分，这里加了一步，应该很清楚。