化简1+sin(x-2π)*cos[x-(7π/2)]-tan(π-x)*tan(3π/2-x)-cos^2(-x)1+sin(x_数学解答

化简1+sin(x-2π)*cos[x-(7π/2)]-tan(π-x)*tan(3π/2-x)-cos^2(-x)
1+sin(x-2π)*cos[x-(7π/2)]-tan(π-x)*tan(3π/2-x)-cos^2(-x) 怎么化啊

人气：473 ℃　时间：2020-05-16 19:23:21

解答

1+sin(x)*cos(x+pi/2)+tan(x)*(-tan(x+pi/2))-(cos(x))^2
=1-(sin(x))^2-(cos(x))^2+ sin(x)/cos(x)*(-sin(x+pi/2)/cos(x+pi/2))
=1-((sin(x))^2+(cos(x))^2)+sin(x)/cos(x)*(-cos(x)/(-sin(x))
=1