f(x)=sin(2x-3/π)+cos(32x-6/π)+cos2x
设y1＝sin(2x-3/π)+cos2x 其最小正周期为π
y2＝cos(32x-6/π ﹚ 其最小正周期为π／16
∴f(x﹚最小正周期为π