不急,三角函数求cosφ
2√2cosφ-√2sinφ＝1
人气：226 ℃ 时间：2020-05-19 12:56:45
解答
√2/2 和 -√2/10.
cos=x,sin=y.
2√2x-√2y=1,(1)
x^2+y^2=1,(2)
联立解出两组解(x,y):(1/√2,1/√2),(-√2/10,-7√2/10).
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