> 数学 >
求下列各式中x的值:(1)x2-25=0 (2)4(x+1)2=81 (3)4x2=64 (4)x2/2-98=0
人气:473 ℃ 时间:2020-06-18 09:47:46
解答
(1)x ² - 25 = 0
x ² = 25
x = ± 5
(2)4(x + 1)² = 81
(x + 1)² = 81 / 4
x + 1 = ± 9 / 2
x = ± 9 / 2 - 1
(3)4 x ² = 64
x ² = 16
x = ± 4
(4)x ² / 2 - 98 = 0
x ² / 2 = 98
x ² = 196
x = ± 14
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版