已知cos(15°+α)=
,α为锐角,求:
| tαn(435°−α)+sin(α−165°) |
| cos(195°+α)×sin(105°+α) |
.
人气:241 ℃ 时间:2020-04-14 20:37:01
解答
∵cos(15°+α)=
,α为锐角,
∴sin(15°+α)=
,
∴cot(15°+α)=
=
.
∴
| tαn(435°−α)+sin(α−165°) |
| cos(195°+α)×sin(105°+α) |
=
| tan(75°−α)−sin(α+15°) |
| −cos(15°+α)•cos(15°+α) |
=
| cot(15°+α)−sin(15°+α) |
| −cos2(15°+α) |
=
=
-
=
.
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