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tanα=-1/3 则sinα^2+2sinαcosα-3cosα^2=?
人气:323 ℃ 时间:2020-05-13 10:26:24
解答
tanα=-1/3 则tanα^2=1/9(sinα^2+2sinαcosα-3cosα^2)/cosα^2=1/tanα^2-3+2xtanα=9-3+(-2/3)=10/3 sinα/cosα=-1/3sinα^2+cosα^2=1cosα^2=9/10sinα^2+2sinαcosα-3cosα^2=3
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