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数学
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方程组
3X+2Y+Z =13
X+Y+2Z =7
2X+3Y-Z =12
人气:436 ℃ 时间:2020-07-06 14:29:17
解答
3X+2Y+Z =13 (1)
X+Y+2Z =7 (2)
2X+3Y-Z =12 (3)
(1)+(3)得5X+5Y=25 (4)
(3)×2+(2)得5X+7Y=31 (5)
(5)-(4)得2Y=6,∴Y=3
代入(4)得X=2
代入(2)得Z=1
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