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数学
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1+1!+2+2!+3+3!+……+n+n!
人气:231 ℃ 时间:2020-06-23 08:33:29
解答
题目也许是
1*1!+2*2!+3*3!+……+n*n!,
它=(2!-1!)+(3!-2!)+(4!-3!)+……+[(n+1)!-n!]
=(n+1)!-1.
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