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因式分解:x2-y2+2x-4y-3
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人气:296 ℃ 时间:2020-09-05 18:32:32
解答
x²-y²+2x-4y-3
=(x²+2x+1)-(y²+4y+4)
=(x+1)²-(y+2)²
=[(x+1)-(y+2)][(x+1)+(y+2)]
=(x-y-1)(x+y+3)
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