解y=x^2和x=y^2组成的方程组x=0 y=0 x=1 y=1得到交坐标为(0,0)(1,1)从图中可看出,所求图形是由x=y^2的上支和y=x^2的右支围成即y1=x^(1/2) y2=x^2其面积=∫(y1-y2)dx [0,1]=∫[x^(1/2)-x^2]dx [0,1]=[(2/3)x^(3...