答：1）(3-4i)/(1+2i)+(2+i^15)-(1-i)^6=(3-4i)(1-2i)/[(1+2i)(1-2i)]+[2+i*(i^2)^7]+(1-2i+i^2)^3=(3-10i+8i^2)/(1-4i^2)+(2-i)+(-2i)^3=(-5-10i)/5+2-i+8i=-1-2i+2+7i=1+5i2)S=i+2i^2+3i^3+.+359i^359两边同乘以i...