1又3分之2减[(3.62乘15分之2加6.38除以7又2分之1)乘1.82减1又3分之1乘0.82]解原式=5/3-[(362/100×2/15+638/100×2/15)×182/100-4/3×82/100]=5/3-[(362/100+638/100)×2/15×182/100-4/3×82/100]=5/3-(10×2/15×...第一题呢(1又1998分之1乘8.12加5又75分之31除以3分之2乘8又1998分之1997)除以4又48分之11=[(1999/1998）×812/100+（406/75)÷(2/3)×(1997+8×1998)/1998]÷203/48=[(1999/1998)×203/25+203/25×(1997+8×1998)1998]÷203/48=1/25×(1999/1998+1997/1998+8)×48=48/25×(2+8)=48×10÷25=19.2