| π |
| 2 |
| π |
| 2 |
而sin(α-β)=
| ||
| 3 |
| π |
| 2 |
∴cos(α-β)=
| 1−sin2(α−β) |
| 2 |
| 3 |
(2)∵tanαtanβ=
| 13 |
| 7 |
∴
| cos(α+β) |
| cos(α−β) |
| cosαcosβ−sinαsinβ |
| cosαcosβ+sinαsinβ |
=
| 1−tanαtanβ |
| 1+tanαtanβ |
1−
| ||
1+
|
| 3 |
| 10 |
又cos(α-β)=
| 2 |
| 3 |
∴cos(α+β)=-
| 1 |
| 5 |
| 13 |
| 7 |
| ||
| 3 |
| π |
| 2 |
| π |
| 2 |
| ||
| 3 |
| π |
| 2 |
| 1−sin2(α−β) |
| 2 |
| 3 |
| 13 |
| 7 |
| cos(α+β) |
| cos(α−β) |
| cosαcosβ−sinαsinβ |
| cosαcosβ+sinαsinβ |
| 1−tanαtanβ |
| 1+tanαtanβ |
1−
| ||
1+
|
| 3 |
| 10 |
| 2 |
| 3 |
| 1 |
| 5 |