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急,已知f(α)=sin(π/2-α)cos(2π-α)tan(-α+3π)/tan(π+α)sin(π/2+α)
(1)化简f(α)
(2)若α是第三象限的角,且cos(α-3π/2)=1/5,求f(α)的值
(3)若α=-1860°,求f(α)的值
人气:281 ℃ 时间:2020-05-19 05:54:23
解答
1f(α)=sin(π/2-α)cos(2π-α)tan(-α+3π)/tan(π+α)sin(π/2+α)=cosα*cosα(-tanα)/(tanαcosα)=-cosα2∵cos(α-3π/2)=1/5∴-sinα=1/5,sinα=-1/5∵α是第三象限的角∴cosα=-√(1-sin...
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