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计算下列各式:(1)5x^-1y^4/4x^2y(2)(x^2-9/x^2-6x+9)^-3
人气:313 ℃ 时间:2020-05-24 03:12:55
解答
(1)5x^-1y^4/4x^2y=5/x*y^4/4x^2y=5/4*x^(1-2)y^(4-2)=5/4*x^-1y^2(2)(x^2-9/x^2-6x+9)^-3=[(x+3)(x-3)/(x-3)^2]^-3=[(x+3)/(x-3)]^-3=1/[(x+3)/(x-3)]^3=1/[(x+3)^3/(x-3)^3]=(x-3)^3/(x+3)^3
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