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x^2y^2-x^2-y^2-bxy+4因式分解
人气:359 ℃ 时间:2020-04-10 12:37:51
解答
你是不是看错题了,是6xy吧.
x²y²-x²-y²-6xy+4
=(x²y²-4xy+4)-(x²+2xy+y²)
=(xy-2)²-(x+y)²
=[(xy-2)+(x+y)][(xy-2)-(x+y)]
=(xy+x+y-2)(xy-x-y-2)
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