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1/1-A称为A的差倒数,已知A1=2,A2是A1的差倒数,A3是A2的差倒数,A4是A3的差倒数,...,依此类推,则A2010=?
人气:117 ℃ 时间:2020-09-27 21:35:38
解答
A1 = 2 ;
A2 = 1/(1-A1) = -1 ;
A3 = 1/(1-A2) = 1/2 ;
A4 = 1/(1-A3) = 2 = A1 ;
可得:A(n+3) = An ,
所以,A2010 = A2007 = A2004 = …… = A3 = 1/2 .
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