f（x)=（x＋1）（x＋2）（x＋3）．．．．．．（x＋100）,
lnf(x)=ln(x+1)+ln(x+2)+...+ln(x+100)
ln'f(x)=f'(x)/f(x)=1/(x+1)+1/(x+2)+.+1/(x+100)
f'(x)=f(x)*[1/(x+1)+1/(x+2)+...+1/(x+100)]
f'(0)=f(0)*[1/(0+1)+1/(0+2)+...+1/(0+100)]
f'(0)=100![1+1/2+1/3+...1/100]