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已知tana=3,求sin平方a-2sinacosa 3cos平方a
人气:447 ℃ 时间:2020-06-20 10:25:23
解答
sin^2a-2sinacosa+3cos^2a
=(sin^2a-2sinacosa+3cos^2a)/(sin^2a+cos^2a)
=(tan^2a-2tana+3)/(tan^2a+1)
=(9-6+3)/(9+1)
=6/10
=3/5
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