=∫sin^2xcos^2xdx=1/4∫sin（2x）dx=-1/8cos（2x）+C好吧我错了…=∫sin^2xcos^2xdx=1/4∫sin^2（2x）dx=1/4∫（sin^2（2x）-1/2+1/2）dx=1/4∫（-1/2cos（4x）+1/2）dx=-1/32sin（4x）+1/8x