直线PA为Y=X+N,直线PB为Y=-2X+M,点Q是PA与Y轴的交点,且四边形PQOB的面积是5/6 AB=2,
求P的坐标及直线PA PB的解析式
人气:356 ℃ 时间:2020-06-12 08:24:09
解答
(1)A(-n,0), B( ,0), P( , ); (2)连接PO,则依题意:m>0,n>0 SΔPOB= OB·|yp|= · · = , SΔPOQ= OQ·|xp|= ·n· = , ∵ S四边形PQOB=SΔPOB+ SΔPOQ = ,AB...
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