tanx=2 求sin^2x+sinxcosx-3cos^2x
人气:296 ℃ 时间:2019-12-27 01:37:37
解答
tanx=2
sinx/cosx=2
sinx=2cosx
(sinx)^2+(cosx)^2=5(cosx)^2=1
(cosx)^2=1/5
(sinx)^2+sinxcosx-3(cosx)^2
=(cosx)^2(4+2-3)
=3(cosx)^2
=3/5
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