(2+2i)/(3^.5-i) = (2+2i)(3^.5+i)/ [ 3+1] =0.5(1+i)(3^.5+i)(2-2i)/(1+3^.5i) = (2-2i)(1-3^.5i)/[1+3] = 0.5(1-i)(1-3^.5i)=-0.5(1+i)(3^.5+i)因此,原式 = 2*[0.5*(1+i)(3^.5+i)]^7 =1/64*(1+i)^7*(3^.5+i)^7(1+i...