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已知数列{log2 (an-1)}为等差数列,且a1=3 a3=9 (1)求an (2)证明1/(a2-a1)+1/(a3
an已经求出,an=2^n +1
(2)证明1/(a2-a1)+1/(a3-a2)+…+1/a(n+1)-an
人气:459 ℃ 时间:2019-08-29 05:10:13
解答
1/(a2-a1)+1/(a3-a2)+…+1/a(n+1)-an
=1/2+1/2^2+…+1/2^n
=1/2+1/2^2+…+1/2^n+1/2^n-1/2^n
=1-1/2^n1/a(n+1)-an为什么成了1/2^n+1/2^n-1/2^n?1/2^n-1/2^n不是等于零吗?1/2^n-1/2^n是怎么来的?+0
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