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sinα-coaα×tanα-sin⁴α-sin²α×cos²α-cos²α=
人气:359 ℃ 时间:2020-02-01 01:23:57
解答
sinα-coaα×tanα-sin⁴α-sin²α×cos²α-cos²α
=sinα-sinα-sin⁴α-sin²α×(1-sin²α)-cos²α
=-sin⁴α-sin²α+sin⁴α-cos²α
=-(sin²α+cos²α)
=-1
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