数学之美团为你解答(x-1)(x-2)(x+2)(x+3)=60[(x-1)(x+2)] [(x-2)(x+3)] = 60(x²+x-2)(x²+x-6)=60(x²+x)²-8(x²+x)+12=60(x²+x)²-8(x²+x)-48=0(x²+x-12)(x²+x+4)=0...