设中间一个数为x,那么另外两个数分别为x+1、x-1,根据题意的x（x^2-1）=120x^3-x-120=0(x^3-125)-(x-5)=0(x-5)(x^2+5x+25)+(x-5)=0(x-5)(x^2+5x+24)=0x-5=0或x^2+5x+24=0当x-5=0时,x=5而对于方程y=x^2+5x+24中△=25-2...