【(1-根号3*i)/(1+i)】^2
＝［（1－根号3i)(1-i)/(1+1)]^2
=[(1-i-根号3i-根号3）／2］^2
=[(1-根号3）－（1＋根号3）i]^2/4
=［(1-根号3）^2-2(1－根号3）（1＋根号3）i-(1+根号3）^2]/4
＝（－4根号3＋4i)/4
=-根号3＋i