[6a^(m+2)b^(n+2)-4a^(m+1)b^(+1)+2a^(m)b^m]÷(-2a^(m)b(n)
=2a^m[3a^2b^(n+2)-2a^b^(+1)+b^m]÷(-2a^(m)b(n)
=[3a^2b^(n+2)-2a^b^(+1)+b^m]÷(-b(n)
=-3a^2b^2+2a^b^(1-n)-b^(m-n)