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1/4+SQR[5A]+30SQR[2]+1/3-SQR[66-40SQR[2]] 怎么计算啊?
人气:320 ℃ 时间:2020-06-16 14:38:37
解答
=(1/4+1/3)+30根号2+根号5A-根号[(5根号2)^2-2*4*(5根号2)+4^2]
=7/12+30根号2+根号5A-(5根号2-4)
=7/12+25根号2+根号5A+4
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