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计算:x²-y²/x·-x²/(x-y)²;8y²y³·(-3x/4y²).
人气:117 ℃ 时间:2019-12-09 21:31:41
解答
(x²-y²)/x·(-x²)/(x-y)²=(x+y)(x-y) ·(-x)/(x-y)²=-x(x+y)/(x-y)
.
8y²y³·(-3x/4y²)=2y³·(-3x)=-6x·y³
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