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根号2·cos(x-2/π)化简为sin(~)的形式
人气:110 ℃ 时间:2020-05-10 06:39:43
解答
由sinx=cos(π/2-x)
2·cos(x-2/π)=2·sin(π/2-(x-2/π))=2·sin(π/2-x+2/π)=2·sin(π/2+2/π-x)
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