(5x-3)(x+1)==(x+1)^2+5,变形4x^2-9==0,因式分解(2x-3)(2x+3)==0,解得x=±1.5
(x+5)^2-2(x+5)-8==0,变形x^2+8x+7==0,因式分解(x+1)(x+7)==0,解得x1=-1, x2=-7
(x-1)(x+2)==70,变形x^2+x-72==0,因式分解(x-8)(x+9)==0,解得x1=8, x2=-9
x^2-(3+2√3)x+5+3√3==0,简便的方法还没想到,解得x1=2+√3, x2=1+√3