题目不清楚啊,那个是几次方啊?
算了,我就按2次方做了啊
2x^2+xy-6y^2
=(2x-3y)(x+2y)
6（x+y)^2-5(x+y)-1
=[6(x+y)+1][(x+y)-1]
=(6x+6y+1)(x+y-1)
(x^2+x)^2-14(x^2+x)^2+24
=(x^2+x-12)(x^2+x-2)
=(x-3)(x+4)(x-1)(x+2)