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求∫(0,1)e^√x dx
人气:108 ℃ 时间:2020-02-03 05:28:55
解答
令:√x = t ,则:x = t^2 ; dx = 2tdt
∫(0,1) e^√x dx
=∫(0,1) e^t (2tdt)
= 2 ∫(0,1) tde^t
= 2 [ te^t|(0,1) -∫(0,1) e^t dt ]
= 2 [ (e-0) - e^t|(0,1) ]
= 2 [ e - (e-1) ]
= 2
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