∵a=√3-√2
==>1/a=1/(√3-√2)=√3+√2
==>a+1/a=√3-√2+√3+√2=2√3
∴a²+1/a²=a²+1/a²+2-2
=(a+1/a)²-2
=(2√3)²-2
=10.