(6*x^2+12*x+10)/(x^2+2*x+2)=[6*(x^2+2*x+2)-2]/(x^2+2*x+2)=6-2/(x^2+2*x+2)=6-2/[(x+1)^2+1]若要分式取得最小值,2/[(x+1)^2+1]应取最大值,分母(x+1)^2+1应取最小值,(x+1)^2的最小值为0,也就是x=-1原分式取得最小...