a(1)＝3 , a(n+1)＝[a(n)]²
a(2)＝[a(1)]²＝3²
a(3)＝[a(2)]²＝[3²]²＝3⁴
a(4)＝[a(3)]²＝[3⁴]²＝3⁸
a(5)＝[a(4)]²＝[3⁸]²＝[3²]⁸
a(n)＝3∧2⁽ⁿ⁻¹⁾,
n＝1,2,3,………
a(1)=3,a(n+1)=a(n)*2,求a(n)
是a(1)=3,a（n+1）=a(n)的平方.求a(n)?
a(1)＝3 , a(n+1)＝[a(n)]²
a(2)＝[a(1)]²＝3²
a(3)＝[a(2)]²＝[3²]²＝3⁴
a(4)＝[a(3)]²＝[3⁴]²＝3⁸
a(5)＝[a(4)]²＝[3⁸]²＝[3²]⁸
a(n)＝3∧2⁽ⁿ⁻¹⁾,
n＝1,2,3,………