n(NaCl)=1.17/58.5=0.02mol
设:Na2CO3 x mol,NaHCO3 y mol
106x+84y=4.13-1.17=2.96g pH=0 c(H+)=1mol/L
2x+y=1.5*0.100-1*0.100=0.05mol
x= 0.02mol y=0.01mol
(1)Na2CO3:0.02*106=2.12g NaHCO3:0.01*84=0.84g
(2)n(AgCl)=n(Cl-)=1.5*0.100+0.02=0.17mol
反应后的溶液中加入足量的AgNO3溶液,可生成沉淀:0.17*143.5=24.395g