{2x-y=3 (1){x²+y²+2x-24=0 (2)由(1)得:y=2x-3 代入(2)得:x²+(2x-3)²+2x-24=0x²-2x-3=0解得:x=-1,x=3y=-5,y=3∴{x=-1,y=-5;{x=3,y=3