设2x^2+3x=m
原式=(m-1)(m-3)-8
=m^2-4m+3-8
=m^2-4m-5
=(m-5)(m+1)
=(2x^2+3x-5)(2x^2+3x+1)
=(x+5)(2x-1)(2x+1)(x+1)
(2x^2+3x-1)(2x^2+3x-3)-8
(2x²+3x-1)(2x²+3x-3)-8 怎么因式分解
设2x^2+3x=m
原式=(m-1)(m-3)-8
=m^2-4m+3-8
=m^2-4m-5
=(m-5)(m+1)
=(2x^2+3x-5)(2x^2+3x+1)
=(x+5)(2x-1)(2x+1)(x+1)