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设函数y=sin(wx-π/3).cos(wx-π/3)的周期为2且w>0则w=
人气:453 ℃ 时间:2024-05-16 21:01:35
解答

∵y=sin(wx-π/3).cos(wx-π/3)y=(1/2)×[2sin(wx-π/3).cos(wx-π/3)]
∴y=(1/2)sin(2wt-2π/3)
∵T=2
∴2W=2π/T=2π/2=π
∴W=π/2
反思:小心2w与w的区别.

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