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简化√((1-cos(2π+θ)/(1+cos(2π+θ))+√((1+cos(2π-θ)/(1-cos(2π-θ))(π<θ<3π/2)答案是-2/sinθ 我要过程快
人气:356 ℃ 时间:2020-06-21 19:27:44
解答
√((1-cos(2π+θ)/(1+cos(2π+θ))+√((1+cos(2π-θ)/(1-cos(2π-θ))
=√((1-cosθ)/(1+cosθ))+√((1+cosθ)/(1-cosθ))
=√((1-cosθ)^2/(1+cosθ)(1-cosθ))+√((1+cosθ)^2/(1+cosθ)(1-cosθ))
=-(1+cosθ)/sinθ-(1-cosθ)/sinθ (π<θ<3π/2)
=-2/sinθ
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